3.12.100 \(\int \frac {(a-i a x)^{5/4}}{(a+i a x)^{7/4}} \, dx\) [1200]

Optimal. Leaf size=113 \[ \frac {4 i (a-i a x)^{5/4}}{3 a (a+i a x)^{3/4}}+\frac {10 i \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}}{3 a}-\frac {10 a \left (1+x^2\right )^{3/4} F\left (\left .\frac {1}{2} \tan ^{-1}(x)\right |2\right )}{3 (a-i a x)^{3/4} (a+i a x)^{3/4}} \]

[Out]

4/3*I*(a-I*a*x)^(5/4)/a/(a+I*a*x)^(3/4)+10/3*I*(a-I*a*x)^(1/4)*(a+I*a*x)^(1/4)/a-10/3*a*(x^2+1)^(3/4)*(cos(1/2
*arctan(x))^2)^(1/2)/cos(1/2*arctan(x))*EllipticF(sin(1/2*arctan(x)),2^(1/2))/(a-I*a*x)^(3/4)/(a+I*a*x)^(3/4)

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Rubi [A]
time = 0.02, antiderivative size = 113, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {49, 52, 42, 239, 237} \begin {gather*} -\frac {10 a \left (x^2+1\right )^{3/4} F\left (\left .\frac {\text {ArcTan}(x)}{2}\right |2\right )}{3 (a+i a x)^{3/4} (a-i a x)^{3/4}}+\frac {4 i (a-i a x)^{5/4}}{3 a (a+i a x)^{3/4}}+\frac {10 i \sqrt [4]{a+i a x} \sqrt [4]{a-i a x}}{3 a} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a - I*a*x)^(5/4)/(a + I*a*x)^(7/4),x]

[Out]

(((4*I)/3)*(a - I*a*x)^(5/4))/(a*(a + I*a*x)^(3/4)) + (((10*I)/3)*(a - I*a*x)^(1/4)*(a + I*a*x)^(1/4))/a - (10
*a*(1 + x^2)^(3/4)*EllipticF[ArcTan[x]/2, 2])/(3*(a - I*a*x)^(3/4)*(a + I*a*x)^(3/4))

Rule 42

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(m_), x_Symbol] :> Dist[(a + b*x)^FracPart[m]*((c + d*x)^Frac
Part[m]/(a*c + b*d*x^2)^FracPart[m]), Int[(a*c + b*d*x^2)^m, x], x] /; FreeQ[{a, b, c, d, m}, x] && EqQ[b*c +
a*d, 0] &&  !IntegerQ[2*m]

Rule 49

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + 1))), x] - Dist[d*(n/(b*(m + 1))), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 52

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + n + 1))), x] + Dist[n*((b*c - a*d)/(b*(m + n + 1))), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 237

Int[((a_) + (b_.)*(x_)^2)^(-3/4), x_Symbol] :> Simp[(2/(a^(3/4)*Rt[b/a, 2]))*EllipticF[(1/2)*ArcTan[Rt[b/a, 2]
*x], 2], x] /; FreeQ[{a, b}, x] && GtQ[a, 0] && PosQ[b/a]

Rule 239

Int[((a_) + (b_.)*(x_)^2)^(-3/4), x_Symbol] :> Dist[(1 + b*(x^2/a))^(3/4)/(a + b*x^2)^(3/4), Int[1/(1 + b*(x^2
/a))^(3/4), x], x] /; FreeQ[{a, b}, x] && PosQ[a]

Rubi steps

\begin {align*} \int \frac {(a-i a x)^{5/4}}{(a+i a x)^{7/4}} \, dx &=\frac {4 i (a-i a x)^{5/4}}{3 a (a+i a x)^{3/4}}-\frac {5}{3} \int \frac {\sqrt [4]{a-i a x}}{(a+i a x)^{3/4}} \, dx\\ &=\frac {4 i (a-i a x)^{5/4}}{3 a (a+i a x)^{3/4}}+\frac {10 i \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}}{3 a}-\frac {1}{3} (5 a) \int \frac {1}{(a-i a x)^{3/4} (a+i a x)^{3/4}} \, dx\\ &=\frac {4 i (a-i a x)^{5/4}}{3 a (a+i a x)^{3/4}}+\frac {10 i \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}}{3 a}-\frac {\left (5 a \left (a^2+a^2 x^2\right )^{3/4}\right ) \int \frac {1}{\left (a^2+a^2 x^2\right )^{3/4}} \, dx}{3 (a-i a x)^{3/4} (a+i a x)^{3/4}}\\ &=\frac {4 i (a-i a x)^{5/4}}{3 a (a+i a x)^{3/4}}+\frac {10 i \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}}{3 a}-\frac {\left (5 a \left (1+x^2\right )^{3/4}\right ) \int \frac {1}{\left (1+x^2\right )^{3/4}} \, dx}{3 (a-i a x)^{3/4} (a+i a x)^{3/4}}\\ &=\frac {4 i (a-i a x)^{5/4}}{3 a (a+i a x)^{3/4}}+\frac {10 i \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}}{3 a}-\frac {10 a \left (1+x^2\right )^{3/4} F\left (\left .\frac {1}{2} \tan ^{-1}(x)\right |2\right )}{3 (a-i a x)^{3/4} (a+i a x)^{3/4}}\\ \end {align*}

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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
time = 10.04, size = 70, normalized size = 0.62 \begin {gather*} \frac {i \sqrt [4]{2} (1+i x)^{3/4} (a-i a x)^{9/4} \, _2F_1\left (\frac {7}{4},\frac {9}{4};\frac {13}{4};\frac {1}{2}-\frac {i x}{2}\right )}{9 a^2 (a+i a x)^{3/4}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a - I*a*x)^(5/4)/(a + I*a*x)^(7/4),x]

[Out]

((I/9)*2^(1/4)*(1 + I*x)^(3/4)*(a - I*a*x)^(9/4)*Hypergeometric2F1[7/4, 9/4, 13/4, 1/2 - (I/2)*x])/(a^2*(a + I
*a*x)^(3/4))

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {\left (-i a x +a \right )^{\frac {5}{4}}}{\left (i a x +a \right )^{\frac {7}{4}}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a-I*a*x)^(5/4)/(a+I*a*x)^(7/4),x)

[Out]

int((a-I*a*x)^(5/4)/(a+I*a*x)^(7/4),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a-I*a*x)^(5/4)/(a+I*a*x)^(7/4),x, algorithm="maxima")

[Out]

integrate((-I*a*x + a)^(5/4)/(I*a*x + a)^(7/4), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a-I*a*x)^(5/4)/(a+I*a*x)^(7/4),x, algorithm="fricas")

[Out]

1/3*(3*(a*x - I*a)*integral(-5/3*(I*a*x + a)^(1/4)*(-I*a*x + a)^(1/4)/(a*x^2 + a), x) - 2*(I*a*x + a)^(1/4)*(-
I*a*x + a)^(1/4)*(-3*I*x - 7))/(a*x - I*a)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (- i a \left (x + i\right )\right )^{\frac {5}{4}}}{\left (i a \left (x - i\right )\right )^{\frac {7}{4}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a-I*a*x)**(5/4)/(a+I*a*x)**(7/4),x)

[Out]

Integral((-I*a*(x + I))**(5/4)/(I*a*(x - I))**(7/4), x)

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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a-I*a*x)^(5/4)/(a+I*a*x)^(7/4),x, algorithm="giac")

[Out]

Exception raised: RuntimeError >> An error occurred running a Giac command:INPUT:sage2OUTPUT:ext_reduce Error:
Bad Argument Typeintegrate(-(-i)/4*16*((sageVARa+(-i)*sageVARa*sageVARx)^(1/4))^8/(-((sageVARa+(-i)*sageVARa*
sageVARx)^(1/4

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (a-a\,x\,1{}\mathrm {i}\right )}^{5/4}}{{\left (a+a\,x\,1{}\mathrm {i}\right )}^{7/4}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a - a*x*1i)^(5/4)/(a + a*x*1i)^(7/4),x)

[Out]

int((a - a*x*1i)^(5/4)/(a + a*x*1i)^(7/4), x)

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